By Kedlaya K.S.

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J | > 1 and |αj+1 | ≤ 1, |αj+2 | ≤ 1, . . , |αn | ≤ 1. Prove that j i=1 |αi | ≤ |a0 |2 + |a1 |2 + · · · + |an |2 . ) 6. Prove that, for any real numbers x, y, z, 3(x2 − x + 1)(y 2 − y + 1)(z 2 − z + 1) ≥ (xyz)2 + xyz + 1. 7. (a) Prove that any polynomial P (x) such that P (x) ≥ 0 for all real x can be written as the sum of the squares of two polynomials. (b) Prove that the polynomial x2 (x2 − y 2 )(x2 − 1) + y 2 (y 2 − 1)(y 2 − x2 ) + (1 − x2 )(1 − y 2 ) is everywhere nonnegative, but cannot be written as the sum of squares of any number of polynomials.

So f is convex if and only if Hy · y > 0 for all nonzero y, that is, if H is positive definite. The bad news about this criterion is that determining whether a matrix is positive definite is not a priori an easy task: one cannot check M x · x ≥ 0 for every vector, so it seems one must compute all of the eigenvalues of M , which can be quite a headache. The good news is that there is a very nice criterion for positive definiteness of a symmetric matrix, due to Sylvester, that saves a lot of work.

Popoviciu, Asupra mediilor aritmetice si medie geometrice (Romanian), Gaz. Mat. Bucharest 40 (1934), 155-160. [4] S. Rabinowitz, Index to Mathematical Problems 1980-1984, Mathpro Press, Westford (Massachusetts), 1992.

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A is less than B by Kedlaya K.S.

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